举例说明:
1、当两个并发线程访问同一个对象object中的这个synchronized(this)同步代码块时,一个时间内只能有一个线程获得执行。另外一个线程必须等待当前线程执行完这个代码块之后才能执行该代码块。并发
package ths;oop
public class Thread1 implements Runnable {
public void run() {
synchronized(this) {
for (int i = 0; i < 5; i++) {
System.out.println(Thread.currentThread().getName() + " synchronized loop " + i);
}
}
}
public static void main(String[] args) {
Thread1 t1 = new Thread1();
Thread ta = new Thread(t1, "A");
Thread tb = new Thread(t1, "B");
ta.start();
tb.start();
}
}this
结果:
A synchronized loop 0
A synchronized loop 1
A synchronized loop 2
A synchronized loop 3
A synchronized loop 4
B synchronized loop 0
B synchronized loop 1
B synchronized loop 2
B synchronized loop 3
B synchronized loop 4线程
2、然而,当一个线程访问object的一个synchronized(this)同步代码块时,另外一个线程仍然能够访问该object中的非synchronized(this)同步代码块。对象
package ths;get
public class Thread2 {
public void m4t1() {
synchronized(this) {
int i = 5;
while( i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : " + i);
try {
Thread.sleep(500);
} catch (InterruptedException ie) {
}
}
}
}
public void m4t2() {
int i = 5;
while( i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : " + i);
try {
Thread.sleep(500);
} catch (InterruptedException ie) {
}
}
}
public static void main(String[] args) {
final Thread2 myt2 = new Thread2();
Thread t1 = new Thread( new Runnable() { public void run() { myt2.m4t1(); } }, "t1" );
Thread t2 = new Thread( new Runnable() { public void run() { myt2.m4t2(); } }, "t2" );
t1.start();
t2.start();
}
}同步
结果:
t1 : 4
t2 : 4
t1 : 3
t2 : 3
t1 : 2
t2 : 2
t1 : 1
t2 : 1
t1 : 0
t2 : 0io
3、尤为关键的是,当一个线程访问object的一个synchronized(this)同步代码块时,其余线程对object中全部其它synchronized(this)同步代码块的访问将被阻塞。class
//修改Thread2.m4t2()方法:
public void m4t2() {
synchronized(this) {
int i = 5;
while( i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : " + i);
try {
Thread.sleep(500);
} catch (InterruptedException ie) {
}
}
}object
}
结果:
t1 : 4
t1 : 3
t1 : 2
t1 : 1
t1 : 0
t2 : 4
t2 : 3
t2 : 2
t2 : 1
t2 : 0
4、第三个例子一样适用其它同步代码块。也就是说,当一个线程访问object的一个synchronized(this)同步代码块时,它就得到了这个object的对象锁。结果,其它线程对该object对象全部同步代码部分的访问都被暂时阻塞。
//修改Thread2.m4t2()方法以下:
public synchronized void m4t2() {
int i = 5;
while( i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : " + i);
try {
Thread.sleep(500);
} catch (InterruptedException ie) {
}
}
}
结果:
t1 : 4
t1 : 3
t1 : 2
t1 : 1
t1 : 0
t2 : 4
t2 : 3
t2 : 2
t2 : 1
t2 : 0
5、以上规则对其它对象锁一样适用:
package ths;
public class Thread3 {
class Inner {
private void m4t1() {
int i = 5;
while(i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : Inner.m4t1()=" + i);
try {
Thread.sleep(500);
} catch(InterruptedException ie) {
}
}
}
private void m4t2() {
int i = 5;
while(i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : Inner.m4t2()=" + i);
try {
Thread.sleep(500);
} catch(InterruptedException ie) {
}
}
}
}
private void m4t1(Inner inner) {
synchronized(inner) { //使用对象锁
inner.m4t1();
}
private void m4t2(Inner inner) {
inner.m4t2();
}
public static void main(String[] args) {
final Thread3 myt3 = new Thread3();
final Inner inner = myt3.new Inner();
Thread t1 = new Thread( new Runnable() {public void run() { myt3.m4t1(inner);} }, "t1");
Thread t2 = new Thread( new Runnable() {public void run() { myt3.m4t2(inner);} }, "t2");
t1.start();
t2.start();
}
}
结果:
尽管线程t1得到了对Inner的对象锁,但因为线程t2访问的是同一个Inner中的非同步部分。因此两个线程互不干扰。
t1 : Inner.m4t1()=4
t2 : Inner.m4t2()=4
t1 : Inner.m4t1()=3
t2 : Inner.m4t2()=3
t1 : Inner.m4t1()=2
t2 : Inner.m4t2()=2
t1 : Inner.m4t1()=1
t2 : Inner.m4t2()=1
t1 : Inner.m4t1()=0
t2 : Inner.m4t2()=0
如今在Inner.m4t2()前面加上synchronized:
private synchronized void m4t2() {
int i = 5;
while(i-- > 0) {
System.out.println(Thread.currentThread().getName() + " : Inner.m4t2()=" + i);
try {
Thread.sleep(500);
} catch(InterruptedException ie) {
}
}
}
结果:
尽管线程t1与t2访问了同一个Inner对象中两个绝不相关的部分,但由于t1先得到了对Inner的对象锁,因此t2对Inner.m4t2()的访问也被阻塞,由于m4t2()是Inner中的一个同步方法。
t1 : Inner.m4t1()=4 t1 : Inner.m4t1()=3 t1 : Inner.m4t1()=2 t1 : Inner.m4t1()=1 t1 : Inner.m4t1()=0 t2 : Inner.m4t2()=4 t2 : Inner.m4t2()=3 t2 : Inner.m4t2()=2 t2 : Inner.m4t2()=1 t2 : Inner.m4t2()=0