dom反转
最近听好多人说面试的时候，有个dom反转的题，完全没听过啊，应该怎么做，就试着做了一下，
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>
</title>
<script src="js/jquery-1.11.0.min.js">
</script>
<style>
.div1{
width: 400px;
height: 400px;
background: red;
}
.div2{
width: 300px;
height: 300px;
background: green;
}
.div3{
width: 200px;
height: 200px;
background:black;
}
.div4{
width: 100px;
height: 100px;
background: yellow;
}
</style>
</head>
<body>
<div class="div1">
<div class="div2">
<div class="div3">
<div class="div4"></div>
</div>
</div>
</div>
</body>
<script>
$(function(){
var divli = $("body").find("div");
console.log(divli)
var list1 = [];
for(var i=0;i<divli.length; i++){
list1.push($(divli[i]).attr("class"));
}
console.log(list1) ;
var list2 = list1.reverse();
console.log(list2) ;
for(var i=0;i<divli.length; i++){
$(divli[i]).attr("class"," ").addClass(list2[i]);
}
})
</script>
</html>
如果大家有更好更简洁的思路，可以在下面贴出答案