55. Jump Game——python——greedy

时间 2020-12-30

原文原文链接

题目分析：每次记录到达的最远位置，只是当前情况下的最优解。属于贪心算法。 class Solution(object): def repeatedNTimes(self, nums): # 贪心算法 reach = 0 for i, num in enumerate(nums): if i > reach:

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1. (Greedy) leetcode 55. 45. Jump Game I II
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7. LeetCode 55. Jump Game & 45. Jump Game II题解
8. [LeetCode] 55. Jump Game & 45. Jump Game II
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10. leetcode [Greedy] No.45 Jump Game II
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