Guava学习笔记-自定义迭代器

###问题描述
实现一个跳过null值的迭代器
[null,"1","2","3",null,"4",null]->["1","2","3","4"]
[null]->[]
[]->[]
###原来

Iterator<String> iterator = new Iterator<String>() {
    private Iterator<String> sourceIterator = source.iterator();
    private String next;
    public boolean hasNext() {
        while (sourceIterator.hasNext()) {
            next = sourceIterator.next();
            if (next != null) {
                return true;
            }
        }
        next = null;
        return false;
    }

    public String next() {
        while (next == null) {
            next = sourceIterator.next();
        }
        String temp = next;
        next = null;
        return temp;
    }

    public void remove() {
    }
};

我须要写的如此复杂，才能保持Iterator特性，针对第一个case连续调用5次next方法抛出异常
###使用Guava

Iterator<String> iterator = new AbstractIterator<String>() {
    private Iterator<String> sourceIterator = source.iterator();
    @Override protected String computeNext() {
        while (sourceIterator.hasNext()) {
            String next = sourceIterator.next();
            if (next != null) {
                return next;
            }
        }
        return endOfData();
    }
};

只须要关注如何获取下一个值就能够了，不须要关注如何实现hasNext方法。
须要注意：AbstractIterator不支持remove方法