1、位操做:java
shl(bits) – 左移位 (Java’s <<)
shr(bits) – 右移位 (Java’s >>)
ushr(bits) – 无符号右移位 (Java’s >>>)
and(bits) – 与 &
or(bits) – 或 ||
xor(bits) – 异或
inv() – 反向
数组
val a = 5 val b = a shl 2 //左移2位,5*2*2=20 println(b) //20
2、位运算符:code
运算符 | 表示含义 |
---|---|
and(bits) | 按位与 |
or(bits) | 按位或 |
inv(bits) | 按位非 |
xor(bits) | 按位异或 |
shl(bits) | 左移运算符 |
shr(bits) | 右移运算符 |
ushr(bits) | 无符号右移运算符 |
注意:Kotlin的位运算符只能对Int和Long两种数据类型起做用。内存
(src[i].toInt().ushr(4)) and 0x0F)
3、位操做和位运算实例ci
经过位运算来保证头尾不超过数组范围,经过位操做来扩容(数组长度保持为2的整数倍,方便进行位运算)element
//如ArrayDeque经过位与运算(等价于java中的'&'),保证头尾不超过数组边界 class SimpleIntArrayDeque { private var elements: Array<Int?> = arrayOfNulls(16) //扩容数组 private var head: Int = 0 //头 private var tail: Int = elements.size //尾,tail-1是当前最后一位数据 fun addFirst(value: Int) { if (value == null) throw NullPointerException() //当head-1为-1时,其实是11111111&00111111,结果是00111111,也就是物理数组的尾部15; head = (head - 1) and (elements.size - 1) elements[head] = value if (head == tail) doubleCapacity() } fun addLast(value: Int) { if (value == null) throw NullPointerException() elements[tail] = value //当tail+1为16时,其实是01000000&00111111,结果是00000000,也就是物理数组的头部0; tail = (tail + 1) and (elements.size - 1) if (tail == head) doubleCapacity() } fun pollFirst(): Int? { val h = head val result = elements[h] if (result != null) { elements[h] = null head = (h + 1) and (elements.size - 1) } return result } fun pollLast(): Int? { val t = (tail - 1) and (elements.size - 1) val result = elements[t] if (result != null) { elements[t] = null tail = t } return result } //扩容:插入数据前,判断插入后将头尾相等(即插入后数组将填满),则当即扩容 private fun doubleCapacity() { val p = head val n = elements.size val r = n - p var newCapacity = n shl 1 //扩容2倍 if (newCapacity < 0) throw IllegalArgumentException("Sorry, deque too big") var newElements: Array<Int?> = arrayOfNulls(newCapacity) //从头部开始拷贝,拷贝头部之后的全部内容,并把头部位置重置为0 System.arraycopy(elements, p, newElements, 0, r) /** * 从0开始拷贝,拷贝头部以前的内容,并把拷贝内容接上刚才拷贝的位置, * 使得原来的数组放到新数组的前半部分 */ System.arraycopy(elements, 0, newElements, r, p) //释放旧的数组内存 Arrays.fill(elements, null) elements = newElements head = 0 tail = n } fun size(): Int { //插入前判断,若插入后占满则当即扩容,所以size不会大于数组长度减一 return (tail - head) and (elements.size - 1) } fun isEmpty(): Boolean { return head == tail } fun peekFirst(): Int? { return elements[head] } fun peekLast(): Int? { return elements[(tail -1) and (elements.size - 1)] } }