需求:对一张用户表根据name/email/card_num字段去除重复数据;函数
思路:用group by方法能够查询出'去重'后的数据,将这些数据存储到一张临时表中,而后将临时表的数据存储到指定的表中;测试
误区及解决方案:group by方法只能获取部分字段(去重指定字段),不能一次获取到完整的数据,可是能够经过max函数获取group by结果集中的id,再根据id集合查询出所有的记录。code
SELECT max(id) as id,name,email,card_num FROM users GROUP BY name,email,card_num;
email
SELECT ID from (SELECT max(id) as id,name,email,card_num FROM users GROUP BY name,email,card_num) as T;
select
SELECT * from users where id in (SELECT ID from (SELECT max(id) as id,name,email,card_num FROM users GROUP BY name,email,card_num) as T);
方法
create TEMP TABLE tmp_data as SELECT * from users where id in (SELECT ID from (SELECT max(id) as id,name,email,card_num FROM users GROUP BY name,email,card_num) as T);
数据
insert into users_copy1 select * from tmp_data;
查询
select count(*) from users_copy1;
集合