一般咱们比较两个数据是否相等,可使用以下表达式:less
if (v1 == v2) or if (v1 != v2)
可是在实际项目中,不能使用这样的绝对相等表达式。好比1和0.9998实际上也是能够认为是相等的;又好比,设置某个电压参数,set_voltage = 100,000V,100KV后,经过传感器读取实际电压值:read_voltage = 100,005V 或 99,998V,然而这样的偏差其实是被容许的偏差,因为硬件的物理特性,不可能真正作到100%的目标电压,只能尽量的接近目标电压。为此在比较数据,尤为是浮点数据时,一般须要自定义浮点比较函数。函数
通用的浮点比较函数:单元测试
bool equal(double v1, double v2, double precision) { double unprecision = (precision < 0) ? (-1)*precision : precision; double dt = ((v1 < v2) ? v2 : v1) - ((v1 < v2) ? v1 : v2); return (dt > unprecision) ? false : true; } bool greater(double v1, double v2, double precision) { if (equal(v1, v2, precision)) { return false; } else { return (v1 > v2) ? true : false; } } bool less(double v1, double v2, double precision) { if (equal(v1, v2, precision)) { return false; } else { return (v1 < v2) ? true : false; } }
传递一个precision用来控制精度,equal是主要的比较函数,greater和less是在equal的基础上进行比较。测试
double dt = ((v1 < v2) ? v2 : v1) - ((v1 < v2) ? v1 : v2);也能够用double dt = fabs(v1-v2);这里为了减小函数的调用,直接使用了代码;也能够声明为inline函数。大数据
测试代码:code
//循环测试打印 void equal_print(double base, double precision, const double* dt, int size, const char* true_flag, const char* false_flag, function<bool(double,double,double)> func) { for (auto i=0; i<size; i++) { if (func(base, base+*(dt+i), precision)) { printf("%f %s %f, precision = %f\n", base, true_flag, base+dt[i], precision); } else { printf("%f %s %f, precision = %f\n", base, false_flag, base+dt[i], precision); } } } //单元测试 void equal_unit_test() { //超大数据200000正负10之内 double precision = 10; double baseVal = 200000; double dt1[] = {0.0,0.1,-0.1,0.5,-0.5,1,-1,2,-2,5,-5,10,-10,10.1,-10.1,12,-12}; cout << "Test : 200000+10 >= x >= 200000-10" << endl; equal_print(baseVal, precision, &dt1[0], sizeof(dt1)/sizeof(double), "==", "!=", &xpod_common::equal); cout << endl << endl; //高精度数据1正负0.001之内 precision = 0.001; baseVal = 1.0; double dt2[] = {0.0,0.0001,-0.0001,0.0005,-0.0005,0.001,-0.001,0.00101,-0.00101,0.0011,-0.0011,0.002,-0.002}; cout << "Test : 1+0.001 >= x >= 1-0.001" << endl; equal_print(baseVal, precision, &dt2[0], sizeof(dt2)/sizeof(double), "==", "!=", &xpod_common::equal); //大于比较 precision = 0.1; baseVal = 100.0; double dt3[] = {-1,-0.2,-0.11,-0.10,-0.05,-0.01,0.0,0.01,0.05,0.1,0.5,1,2}; cout << "Test : Greator" << endl; equal_print(baseVal, precision, &dt3[0], sizeof(dt3)/sizeof(double), ">", "<>", &xpod_common::greater); cout << endl << endl; //小于比较 cout << "Test : Less" << endl; equal_print(baseVal, precision, &dt3[0], sizeof(dt3)/sizeof(double), "<", "<>", &xpod_common::less); } int main(int argc, char *argv[]) { //test equal equal_unit_test(); return 0; }
测试结果:ci
Test : 1+0.001 >= x >= 1-0.001 1.000000 == 1.000000, precision = 0.001000 1.000000 == 1.000100, precision = 0.001000 1.000000 == 0.999900, precision = 0.001000 1.000000 == 1.000500, precision = 0.001000 1.000000 == 0.999500, precision = 0.001000 1.000000 == 1.001000, precision = 0.001000 1.000000 != 0.999000, precision = 0.001000 1.000000 != 1.001010, precision = 0.001000 1.000000 != 0.998990, precision = 0.001000 1.000000 != 1.001100, precision = 0.001000 1.000000 != 0.998900, precision = 0.001000 1.000000 != 1.002000, precision = 0.001000 1.000000 != 0.998000, precision = 0.001000 Test : Greator 100.000000 > 99.000000, precision = 0.100000 100.000000 > 99.800000, precision = 0.100000 100.000000 > 99.890000, precision = 0.100000 100.000000 <> 99.900000, precision = 0.100000 100.000000 <> 99.950000, precision = 0.100000 100.000000 <> 99.990000, precision = 0.100000 100.000000 <> 100.000000, precision = 0.100000 100.000000 <> 100.010000, precision = 0.100000 100.000000 <> 100.050000, precision = 0.100000 100.000000 <> 100.100000, precision = 0.100000 100.000000 <> 100.500000, precision = 0.100000 100.000000 <> 101.000000, precision = 0.100000 100.000000 <> 102.000000, precision = 0.100000 Test : Less 100.000000 <> 99.000000, precision = 0.100000 100.000000 <> 99.800000, precision = 0.100000 100.000000 <> 99.890000, precision = 0.100000 100.000000 <> 99.900000, precision = 0.100000 100.000000 <> 99.950000, precision = 0.100000 100.000000 <> 99.990000, precision = 0.100000 100.000000 <> 100.000000, precision = 0.100000 100.000000 <> 100.010000, precision = 0.100000 100.000000 <> 100.050000, precision = 0.100000 100.000000 <> 100.100000, precision = 0.100000 100.000000 < 100.500000, precision = 0.100000 100.000000 < 101.000000, precision = 0.100000 100.000000 < 102.000000, precision = 0.100000
输出结果第8行有错误,对应第7行,也应该是相等的才对。这是由于计算机在表示浮点数时,不是完整的精确值,其有必定的偏差,好比计算机可能用0.9998来表示1,所以当精度要求很高时,可能会带来误差。为解决这个问题,在工程计算上通常会将高精度浮点数升级为整数后再计算精度。it