本人在用UiAutomator作测试的时候,常常会遇到一些控件由于不一样的条件显示不一样的颜色,在学习了UiAutomator图像处理以后,本身尝试写了一个方法来处理不一样颜色控件的区分。分享代码供你们参考。java
//根据颜色判断状态 public boolean isBlue(UiObject uiObject) throws UiObjectNotFoundException { screenShot("test");//截图 String path = "/mnt/sdcard/123/test.png"; Bitmap bitmap = BitmapFactory.decodeFile(path);//新建并实例化bitmap对象 Rect rect = uiObject.getVisibleBounds(); int x = rect.left; int xx = rect.right; int y = rect.top; int yy = rect.bottom; List<Integer> blueColor = new ArrayList<Integer>(); for (int i = x; i < xx; i++) { for (int k = y;k < yy;k++) { int color = bitmap.getPixel(i, k);//获取坐标点像素颜色 int red = Color.blue(color); blueColor.add(red); } } int sum = 0; for (int i = 0;i<blueColor.size();i++) { sum += blueColor.get(i); } // output(sum/blueColor.size()); return sum/blueColor.size() > 200?true:false; }
下面是在选择断定值的过程当中快速获取某点颜色值的方法:编程
public int getRedPixel(int x, int y) { screenShot("test");//截图 String path = "/mnt/sdcard/123/test.png"; Bitmap bitmap = BitmapFactory.decodeFile(path);//新建并实例化bitmap对象 int color = bitmap.getPixel(x, y);//获取坐标点像素颜色 // output(color);//输出颜色值 int red = Color.red(color); return red; } public int getGreenPixel(int x, int y) { screenShot("test");//截图 String path = "/mnt/sdcard/123/test.png"; Bitmap bitmap = BitmapFactory.decodeFile(path);//新建并实例化bitmap对象 int color = bitmap.getPixel(x, y);//获取坐标点像素颜色 // output(color);//输出颜色值 int green = Color.green(color); return green; } public int getBluePixel(int x, int y) { screenShot("test");//截图 String path = "/mnt/sdcard/123/test.png"; Bitmap bitmap = BitmapFactory.decodeFile(path);//新建并实例化bitmap对象 int color = bitmap.getPixel(x, y);//获取坐标点像素颜色 // output(color);//输出颜色值 int blue = Color.blue(color); return blue; }
public int[] getRGBcolorPixel(int x, int y) { screenShot("testDemo"); String path = "/mnt/sdcard/123/testDemo.png"; Bitmap bitmap = BitmapFactory.decodeFile(path); int color = bitmap.getPixel(x, y); int red = Color.red(color); int green = Color.green(color); int blue = Color.blue(color); int[] rgb = {red, green, blue}; return rgb; }