Write a function that reverses a string. The input string is given as an array of characters char[].git
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.github
You may assume all the characters consist of printable ascii characters.数组
Example 1:函数
Input: ["h","e","l","l","o"]
Output: ["o","l","l","e","h"]
Example 2:ui
Input: ["H","a","n","n","a","h"]
Output: ["h","a","n","n","a","H"]this
编写一个函数,其做用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。spa
不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。code
你能够假设数组中的全部字符都是 ASCII 码表中的可打印字符。索引
示例 1:ip
输入:["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:
输入:["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]
# -*- coding: utf-8 -*- # @Author: 何睿 # @Create Date: 2019-04-08 21:47:07 # @Last Modified by: 何睿 # @Last Modified time: 2019-04-08 21:54:18 class Solution: def reverseString(self, s: [str]) -> None: """ Do not return anything, modify s in-place instead. """ # 中间位置的索引,最后一个位置的索引 half, count = len(s) // 2, len(s) - 1 for i in range(half): s[i], s[count - i] = s[count - i], s[i]