假设某应用中有如下三个页面:javascript
登录页----Home.jsx 页面A----PageA.jsx 页面B----PageB.jsx
有如下三种用户:java
游客(未登陆)---只能访问登录页 普通用户(已登录)---能访问登录页及页面A 管理员(已登录)---能访问全部页面
具体需求以下:react
因此首先将是否登录做为第一层权限:react-router
withUserPermission.jsx
代码以下app
import React from 'react';
import { Redirect } from 'react-router-dom';
import { getUser } from '@/user.js'; // 判断是否已登录用户
export default Wrapper => hocProps => {
const { component: Component, ...rest } = hocProps;
const user = getUser();
return (
<Wrapper {...rest} component={ props => {
return user
? <Component {...props} />
: <Redirect to="/login" /> // 跳转到登录页
} } />
);
}
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而后在第二层权限,判断是否具备管理员权限: withAdminPermission.jsx
代码以下dom
import React from 'react';
import { getRole } from '@/user.js'; // 获取用户角色
export default Wrapper => hocProps => {
const { component: Component, ...rest } = hocProps;
const hasPermission = (getRole() === 'admin') ;
return (
<Wrapper {...rest} component={ props => {
return hasPermission
? <Component {...props} />
: <h1>无权限访问</h1>
} } />
);
}
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使用这两个高阶组件,封装Routespa
PrivateRoutes.js
代码以下rest
import { Route } from 'react-router-dom';
import withUserPermission from './withUserPermission';
import withAdminPermission from './withAdminPermission';
export const UserRoute = withUserPermission(Route);
export const AdminRoute = withUserPermission(withAdminPermission(Route)); // 从外向内提高权限
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下面能够使用这两个封装好的Route组件,实现上面的需求:code
import React from 'react';
import { BrowserRouter as Router, Route } from 'react-router-dom';
import { UserRoute, AdminRoute } from './PrivateRoutes';
import PageLogin from 'views/PageLogin';
import PageA from 'views/PageA';
import PageB from 'views/PageB';
export default () => (
<Router>
<Route path='/login' component={PageLogin} />
<UserRoute path='/pageA' component={PageA} />
<AdminRoute path='/pageB' component={PageB} />
</Router>
);
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