spring data jpa 先排序后分组

 repository层用:
@Query(value = "select myTemperature2 from (select myTemperature from Temperature myTemperature  order by myTemperature.id.time desc) myTemperature1 group by substr(myTemperature1.id.time, 1, 10)")

启服务的时候报错了 java

解决方案:spa

@PersistenceContext
private EntityManager entityManager;
String queryString="select * from (select * from Temperature t  order by time desc) t1 group by     substr(t1.time, 1, 10)";
javax.persistence.Query query = entityManager.createNativeQuery(queryString,Temperature.class);
List<Temperature> res=query.getResultList();
System.out.println("##$$$$");
System.out.println(res);
System.out.println("##$$$$");
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