登陆接口练习python
要求:读取账号文件,登陆三次错误密码将锁定并写入锁定文件ide
# python 3.6 登陆接口练习 # _*_ coding:utf-8 _*_ import sys import os import getpass i=0 while i < 3 : username = input("请输入用户名:") with open("account_lock.txt","r") as account_lock_file : #打开锁定用户文件,r为只读 account_lock_list = account_lock_file.readlines() #转换成列表 for lock_name in account_lock_list : #循环遍历文件 lock_name = lock_name.strip('\n') #去掉换行符 if username == lock_name : sys.exit("用户{_username}已被锁定,请联系管理员解锁!!".format(_username=username)) #password =input("请输入密码:") with open("accounts.txt",'r') as account_file : account_list = account_file.readlines() for account_line in account_list : (name,pas) = account_line.strip('\n').split() #去掉换行符,并以,为切片 if username == name : j = 0 while j < 3 : password = getpass.getpass("请输入用户密码:") if password == pas : print("用户{_name}登陆成功".format(_name = username)) sys.exit() else: if j != 2 : print("用户{_name}密码输入错误,请从新输入,还有{d}次机会".format(_name = username,d=2-j)) j = j + 1 else: with open("account_lock.txt",'a+') as account_lock_file : account_lock_file.write(username +'\n') sys.exit("超过最大错误次数,用户{_name}已被锁定,并退出".format(_name=username)) else: pass else: if i != 2 : print("用户{_name}不存在,请从新输入,还有{d}次机会!".format(_name = username,d=2-i)) i = i + 1 #当用户输入用户名错误时增长错误次数 else: sys.exit("用户{_username}不存在,系统即将退出".format(_username=username))