python如何将数组分红几个区间，取每一个区间的最大值存到另外一个数组里

python如何将数组分红几个区间，取每一个区间的最大值存到另外一个数组里
贴吧上有人问python 问题：
有一段数组，把它分红几个区间，取每一个区间的最大值存到另外一个数组里
好比数组a[1,2,3,4,5,6,7,8,9,8,7,6,5,4,3,2,1,0]

看看python培训黄哥所写的2个方法。

第一种方法：

# coding:utf-8
"""
黄哥python远程视频培训班
https://github.com/pythonpeixun/article/blob/master/index.md
黄哥python培训试看视频播放地址
https://github.com/pythonpeixun/article/blob/master/python_shiping.md
咨询qq:1465376564
"""


lst = [1, 2, 3, 4, 5, 6, 7, 8, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]


def group(lst, n):
    num = len(lst) % n
    zipped = zip(*[iter(lst)] * n)
    return zipped if not num else zipped + [lst[-num:], ]

tmp = group(lst, 3)
max_lst = [max(item) for item in tmp]
print max_lst
#[3, 6, 9, 8, 5, 2]


第二种方法

# coding:utf-8
"""
黄哥python远程视频培训班
https://github.com/pythonpeixun/article/blob/master/index.md
黄哥python培训试看视频播放地址
https://github.com/pythonpeixun/article/blob/master/python_shiping.md
咨询qq:1465376564
"""


def group(seq, size):

    def take(seq, n):

        for i in xrange(n):

            yield seq.next()

    if not hasattr(seq, 'next'):

        seq = iter(seq)

    while True:

        x = list(take(seq, size))

        if x:

            yield x

        else:

            break


lst = [1, 2, 3, 4, 5, 6, 7, 8, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
lst_group = group(lst, 3)
max_lst = [max(item) for item in list(lst_group)]
print max_lst