有这样一个json串sql
{"viewdata":[{"city_id":"59","position_id":0,"qd_title":"网红打卡地","list_id":35},{"city_id":"59","position_id":1,"qd_title":"看青山游绿水","list_id":37}]}
复制代码
须要将json数组里的qd_title都提取出来转换成hive中的array数组。下面介绍两种方法json
1.首先能够使用get_json_object
函数,提取出数组,可是这个返回的是一个字符串数组
select get_json_object('{"viewdata":[{"city_id":"39","position_id":0,"qd_title":"网红打卡地","list_id":135}, {"city_id":"39","position_id":1,"qd_title":"看青山游绿水","list_id":327}]}',
'$.viewdata[*].qd_title')
-- 返回,注意这不是一个array数组,只是一个字符串
["网红打卡地","看青山游绿水"]
复制代码
2.将字符串中的[ ] "
都去掉,造成一个,
分割的字符串bash
regexp_replace('${刚刚获得的字符串}','(\\[|\\]|")','')
复制代码
3.使用字符串分割函数split函数
select
split(
regexp_replace(
get_json_object('{"viewdata":[{"city_id":"39","position_id":0,"qd_title":"网红打 卡地","list_id":135}, {"city_id":"39","position_id":1,"qd_title":"看青山游绿水","list_id":327}]}',
'$.viewdata[*].qd_title'),
'(\\[|\\]|")',''),
",")
复制代码
4.总体使用LATERAL VIEW 打平数组进行统计ui
SELECT qdtitle,COUNT(DISTINCT uuid) uv
FROM ba_travel.bas_log_sdk_mt_mv a LATERAL VIEW explode(split(regexp_replace(get_json_object(a.event_attribute['custom'],'$.viewdata[*].qd_title'),'(\\[|\\]|")',''),",")) b AS qdtitle
GROUP BY qdtitle
复制代码
1.观察json数组中每个元素都是由{}
保卫,由,
分割,因此能够使用``},```对字符串进行拆分spa
-- event_attribute['custom'] 对应的就是上面的json字符串
split(event_attribute['custom'],'"}')
复制代码
2.对分割出来的每个元素进行正则匹配,提取出qd_title对应的valuecode
-- qd_titles 为上面分割出数组的一个元素
regexp_extract(qd_titles,'qd_title...([^"]+)',1)
复制代码
3.总体使用later view 将数组打平regexp
SELECT regexp_extract(qd_titles,'qd_title...([^"]+)',1) title,
COUNT(DISTINCT uuid) uv
FROM ba_travel.bas_log_sdk_mt_mv a LATERAL VIEW explode(split(event_attribute['custom'],'"}')) b as qd_titles
GROUP BY regexp_extract(qd_titles,'qd_title...([^"]+)',1)
复制代码