其实前一篇的Mysql 小技巧中having min()的方法是为了本篇准备的。可是当时遇到南墙,此次终于破壁找到方案。java
描述: id (自增),type (aaa, bbb,ccc ,ddd),status(ok,error) 三个字段,每一个type,筛选status='ok'的而且id最小的那一条记录。 mysql
create table having_test (id int(11), type varchar(50),status varchar(50)); mysql> select * from having_test; +------+------+--------+ | id | type | status | +------+------+--------+ | 1 | aaa | ok | | 2 | aaa | error | | 3 | aaa | ok | | 4 | bbb | ok | | 5 | ccc | error | | 6 | ccc | ok | | 7 | ddd | error | +------+------+--------+ mysql> select * from having_test where status='ok' group by type having min(id); +------+------+--------+ | id | type | status | +------+------+--------+ | 1 | aaa | ok | | 4 | bbb | ok | | 6 | ccc | ok | +------+------+--------+
mysql中很简单就实现了,先 group 而后having ,可是hive上不是彻底支持sql语法的,在hive上会不会这么简单呢,答案是否认的。sql
create table tmp_wjk_having_test (id int, type string, status string) ROW FORMAT DELIMITED FIELDS TERMINATED BY '\t' ; load data local inpath '/tmp/load.csv' overwrite into table tmp_wjk_having_test; select * from tmp_wjk_having_test; 1 aaa ok 2 aaa error 3 aaa ok 4 bbb ok 5 ccc error 6 ccc ok 7 ddd error select * from tmp_wjk_having_test where status='ok' group by type having min(id); FAILED: Error in semantic analysis: Line 1:73 Expression not in GROUP BY key 'id' # hive 不支持这种写法。仍是要用子查询 select * from tmp_wjk_having_test t1 join ( select min(id) id from tmp_wjk_having_test where status='ok' group by type) t2 on t1.id=t2.id ; 1 aaa ok 1 4 bbb ok 4 6 ccc ok 6
子查询对于小数据集没有影响,可是应用到大数据上最好的是只过一边表,而后就拿出结果。因此还在想新的方案。大数据
select *,min(id) ii from tmp_wjk_having_test where status='ok' group by type ; aaa 1 1 bbb 4 4 ccc 6 6
这种方案可行。问题点:spa
1. 为何min(id)的条件明明是写到了select 中非where ,可是确起到了筛选的做用?code
2. 为何明明是select * ,min(id) 可是最后是拿到了3列(type , id , min(id) ), 若是写成 select type ,min(id) 就只拿到2列( type ,min(id) ) .string
select type,min(id) ii from tmp_wjk_having_test where status='ok' group by type; aaa 1 bbb 4 ccc 6
++++更新 2014.11.11it
三、通常可行方案:io
2列 : select type,min(id) ii from tmp_wjk_having_test where status='ok' group by type; 多列:select t1.* from having_test t1 join (select name,min(age) mm from having_test group by name ) t2 on t1.name = t2.name and t1.age=t2.mm ;