Calculate a + b and output the sum in standard format — that is, the digits must be separated into groups of three by commas (unless there are less than four digits).ios
Inputgit
Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.less
Output函数
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.spa
Sample Inputcode
-1000000 9orm
Sample Outputblog
-999,991three
题目意思:A+B求和,而后每三位为一个单位加上一个“,”的格式输出。
解题思路:转换成字符串来遍历会很方便,注意如果负数第一位负号也要占位的,而且要求最后一位不能出现“,”,其实能够看看遍历到当前位时剩下的位数如果3的倍数,那么就须要加“,”了。
#include<iostream> #include<algorithm> #include<string> using namespace std; int main() { int a,b,len; int i; string str; cin>>a>>b; str=to_string(a+b); len=str.size(); for(i=0;i<len;i++) { cout<<str[i]; if(str[i]=='-') { continue; } if((len-i-1)%3==0&&i!=len-1) { cout<<","; } } return 0; }
注意这里的to_string是C++11里面string中所包含的函数。
ci