python字典练习题

python字典练习题

写代码：有以下字典
按照要求实现每个功能
dict = {"k1":"v1","k2":"v2","k3":"v3"}
一、请循环遍历出全部的key

dict = {"k1":"v1","k2":"v2","k3":"v3"}

#一、请循环遍历出全部的key
for k in dict:
    print(k)

[root@webserver test]# cat loop_dict_keys.py 
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#一、请循环遍历出全部的key
dict = {"k1":"v1","k2":"v2","k3":"v3"}
for k in dict:
print(k)
[root@webserver test]# python3 loop_dict_keys.py 
k1
k2
k3
[root@webserver test]#

二、请循环遍历出全部的value

#二、请循环遍历出全部的value
for k in dict:
    print(dict[k])

[root@webserver test]# cat loop_dict_values.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#二、请循环遍历出全部的value
dict = {"k1":"v1","k2":"v2","k3":"v3"}
for k in dict:
print(dict[k])

[root@webserver test]# python3 loop_dict_values.py
v1
v2
v3
[root@webserver test]#

三、请循环遍历出全部的key和value

#三、请循环遍历出全部的key和value
for k in dict:
    print(k,dict[k])
    

[root@webserver test]# cat loop_dict_kv.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#一、请循环遍历出全部的key
dict = {"k1":"v1","k2":"v2","k3":"v3"}
for k in dict:
print(k,dict[k])
[root@webserver test]# python3 loop_dict_kv.py
k1 v1
k2 v2
k3 v3
[root@webserver test]#

四、请在字典中增长一个键值对,"k4":"v4"，输出添加后的字典

#四、请在字典中增长一个键值对,"k4":"v4"，输出添加后的字典
dict = {"k1":"v1","k2":"v2","k3":"v3"}
print("dict原来的值: ",dict)
dict["k4"] = "v4"
print("dict新增\"k4\":\"v4\"后的值: ",dict)

[root@webserver test]# cat insert_dict.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#四、请在字典中增长一个键值对,"k4":"v4"，输出添加后的字典
dict = {"k1":"v1","k2":"v2","k3":"v3"}
print("dict原来的值: ",dict)
dict["k4"] = "v4"
print("dict新增\"k4\":\"v4\"后的值: ",dict)
[root@webserver test]# python3 insert_dict.py
dict原来的值: {'k1': 'v1', 'k2': 'v2', 'k3': 'v3'}
dict新增"k4":"v4"后的值: {'k1': 'v1', 'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}
[root@webserver test]#

五、请删除字典中键值对"k1":"v1",并输出删除后的结果

#五、请删除字典中键值对"k1":"v1",并输出删除后的结果
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print("dict删除k1前的值: ",dict)
dict.pop("k1")
print("dict删除k1后的值: ",dict)

[root@webserver test]# cat delete.dict.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#五、请删除字典中键值对"k1":"v1",并输出删除后的结果
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print("dict删除k1前的值: ",dict)
dict.pop("k1")
print("dict删除k1后的值: ",dict)
[root@webserver test]# python3 delete.dict.py
dict删除k1前的值: {'k1': 'v1', 'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}
dict删除k1后的值: {'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}
[root@webserver test]#

六、请删除字典中键"k5"对应的键值对，若是字典中不存在键"k5",则不报错，返回None

dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print(dict)
print("删除不存在的k5,不报错，返回值: ",dict.pop("k5",None))

 

[root@webserver test]# cat not_dict_k.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#六、请删除字典中键"k5"对应的键值对，若是字典中不存在键"k5",则不报错，返回None
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print(dict)
print("删除不存在的k5,不报错，返回值: ",dict.pop("k5",None))

[root@webserver test]# python3 not_dict_k.py
{'k1': 'v1', 'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}
删除不存在的k5,不报错，返回值: None
[root@webserver test]#

七、请获取字典中"k2"对应的值

# 七、请获取字典中"k2"对应的值
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print(dict["k2"])

[root@webserver test]# cat get_exist.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
# 七、请获取字典中"k2"对应的值
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print(dict["k2"])
[root@webserver test]# python3 get_exist.py
v2
[root@webserver test]#

八、请获取字典中"k6"对应的值,若是不存在，则不报错，而且让其返回None。

#八、请获取字典中"k6"对应的值,若是不存在，则不报错，而且让其返回None。
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print("dict值: ",dict)
print(dict.get("k6",None))

#八、请获取字典中"k6"对应的值,若是不存在，则不报错，而且让其返回None。
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print("dict值: ",dict)
print(dict.get("k6",None))
[root@webserver test]# python3 get_not_exist.py
dict值: {'k1': 'v1', 'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}
None
[root@webserver test]#

 九、现有dict2 = {"k1":"v11","a":"b"},经过一行操做使dict2 = {"k1":"v1","k2":"v2","k3":"v3","a":"b"}

#九、现有dict2 = {"k1":"v11","a":"b"},经过一行操做使dict2 = {"k1":"v1","k2":"v2","k3":"v3","a":"b"}
dict = {"k1":"v1","k2":"v2","k3":"v3"}
dict2 = {"k1":"v11","a":"b"}
dict2.update(dict)
print("dict: ",dict)
print("dict2: ",dict2)

[root@webserver test]# cat update_dict_union.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#九、现有dict2 = {"k1":"v11","a":"b"},经过一行操做使dict2 = {"k1":"v1","k2":"v2","k3":"v3","a":"b"}
dict = {"k1":"v1","k2":"v2","k3":"v3"}
dict2 = {"k1":"v11","a":"b"}
dict2.update(dict)
print("dict: ",dict)
print("dict2: ",dict2)
[root@webserver test]# python3 update_dict_union.py
dict: {'k1': 'v1', 'k2': 'v2', 'k3': 'v3'}
dict2: {'k1': 'v1', 'a': 'b', 'k2': 'v2', 'k3': 'v3'}
[root@webserver test]#

十、组合嵌套题。写代码，有以下列表，按照要求实现每个功能

"""
lis = [["k",["qwe",20,{"k1":["tt",3,"1"]},89],"ab"]]
10.一、将列表中的数字变成字符串"100"(用两种方法)
10.二、将列表中的字符串"1"变成数字101(用两种方法)
"""

# 10.1 方法1:
print(lis[0][1][2].get("k1")[0].upper())
# 10.1 方法2:
print(lis[0][1][2].get("k1")[0].swapcase())

# 10.2 方法1:
lis[0][1][2]["k1"][2] = 101
# 10.2 方法2:
lis[0][1][2].get("k1")[2]=101

十一、

按照要求，实现以下功能：

"""
现有一个列表li = [1,2,3,'a',4,'c'],有一个字典(此字典是动态生成的，你并不知道他里面有多少
键值对，因此用dic={}模拟字典；如今须要完成这样的操做：若是该字典没有"k1"这个键，那就建立
这个"k1"键和对应的值(该键对应的值为空列表)，并将列表li中的索引位为奇数对应的元素，添加到
"k1"这个键对应的空列表中。若是该字典中有"k1"这个键，且k1对应的value是列表类型。那就将该列表li
中的索引位为奇数对应的元素，添加到"k1"，这个键对应的值中。
"""
dic = {}
li = [1,2,3,'a',4,'c']
if "k1" not in dic:
    dic.setdefault("k1",[])
    for i in li:
        if li.index(i)%2 == 1:
            dic["k1"].append(i)
        else:
            if type(dic["k1"]) == type([]):
                for i in li:
                    if li.index(i)%2 == 1:
                        dic["k1"].append(i)
            else:
                print("字典K1，VALUE不是列表，没法追加")
print(dic)

[root@webserver test]# cat union_dic_lis.py #!/usr/bin/env python3# -*- coding:utf-8 -*-dic = {}li = [1,2,3,'a',4,'c']if "k1" not in dic: dic.setdefault("k1",[]) for i in li: if li.index(i)%2 == 1: dic["k1"].append(i) else: if type(dic["k1"]) == type([]): for i in li: if li.index(i)%2 == 1: dic["k1"].append(i) else: print("字典K1，VALUE不是列表，没法追加")print(dic)[root@webserver test]# python3 union_dic_lis.py {'k1': [2, 'a', 'c', 2, 2, 'a', 'c', 'a', 2, 'a', 'c', 'c']}[root@webserver test]#