sql -- 获取连续签到的用户列表

时间 2019-11-21

标签 sql 获取连续签到用户列表栏目 SQL 繁體版

原文原文链接

签到表:spa

需求:统计连续签到的用户code

1.根据用户和日期分组blog

select user_name, sign_date from user_sign group by user_name, sign_date order by user_name, sign_date

2.取出行号class

select user_name,
       sign_date,
       if(@tmp = user_name, @rownum := @rownum + 1, @rownum := 1) as num,
       @tmp := user_name
from (select user_name, sign_date from user_sign group by user_name, sign_date order by user_name, sign_date) a,
     (select @rownum := 0, @tmp := '') b  ;

3.使用日期作对比,有则叠加,没有则不叠加date

datediff:返回2个日期之间的间隔天数select

select user_name,
       sign_date,
       if(@tmp = user_name and datediff(sign_date, @date) = 1, @rownum := @rownum + 1, @rownum := 1) as num,
       @tmp := user_name,
       @date := sign_date
from (select user_name, sign_date from user_sign group by user_name, sign_date order by user_name, sign_date) a,
     (select @rownum := 0, @tmp := '', @date := '') b

4.取出连续签到4天的用户列表im

select * from (
select user_name,
       sign_date,
       if(@tmp = user_name and datediff(sign_date, @date) = 1, @rownum := @rownum + 1, @rownum := 1) as num,
       @tmp := user_name,
       @date := sign_date
from (select user_name, sign_date from user_sign group by user_name, sign_date order by user_name, sign_date) a,
     (select @rownum := 0, @tmp := '', @date := '') b  ) c where num=4;