#iOS 获取字符串中的单个字符服务器
要取到单个字符,就要知道字符串的编码方式,这样才可以定位每一个字符在内存中的位置。可是,iOS的字符串编码是不固定的,所以,须要设置一个统一的编码格式,将全部其余格式的字符串都转化为统一的格式,而后就能够根据编码规则取到单个字符了。在这里,使用UTF-8编码。UTF-8编码的使用范围比较普遍,客户端与服务器之间传输的数据大多以UTF-8编码。编码
关于UTF-8的详细说明能够Wiki下:UTF-8。code
下图是UTF-8编码的格式:orm
开发的流程大概是:对象
**有一点要注意:ip
<!-- lang: cpp --> NSString *string = [NSString stringWithFormat:@"1a张"]; const char *chars = [string cStringUsingEncoding:NSUTF8StringEncoding]; for (int i = 0; i < strlen(chars); i++) { printf("%x", chars[i]); }
输出:3161ffffffe5ffffffbcffffffa0内存
在iOS中,非ASCII字符的前面都会加上ffffff,而不是直接使用UTF-8中规定的起始值。开发
下面是代码实现(使用类别):字符串
NSString+StringToWords.hget
<!-- lang: cpp --> #import <Foundation/Foundation.h> @interface NSString (StringToWords) - (NSArray *)words; @end
NSString+StringToWords.h
<!-- lang: cpp --> #import "NSString+StringToWords.h" @implementation NSString (StringToWords) - (NSArray *)words { #if ! __has_feature(objc_arc) NSMutableArray *words = [[[NSMutableArray alloc] init] autorelease]; #else NSMutableArray *words = [[NSMutableArray alloc] init]; #endif const char *str = [self cStringUsingEncoding:NSUTF8StringEncoding]; char *word; for (int i = 0; i < strlen(str);) { int len = 0; if (str[i] >= 0xFFFFFFFC) { len = 6; } else if (str[i] >= 0xFFFFFFF8) { len = 5; } else if (str[i] >= 0xFFFFFFF0) { len = 4; } else if (str[i] >= 0xFFFFFFE0) { len = 3; } else if (str[i] >= 0xFFFFFFC0) { len = 2; } else if (str[i] >= 0x00) { len = 1; } word = malloc(sizeof(char) * (len + 1)); for (int j = 0; j < len; j++) { word[j] = str[j + i]; } word[len] = '\0'; i = i + len; NSString *oneWord = [NSString stringWithCString:word encoding:NSUTF8StringEncoding]; free(word); [words addObject:oneWord]; } return words; } @end